Optimal. Leaf size=252 \[ -\frac{(d+e x)^5}{3 b \left (a^2+2 a b x+b^2 x^2\right )^{3/2}}+\frac{10 e^3 (a+b x) (b d-a e)^2 \log (a+b x)}{b^6 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{20 e^2 (b d-a e)^3}{3 b^6 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{5 e (b d-a e)^4}{6 b^6 (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{5 e^4 x (a+b x) (4 b d-3 a e)}{3 b^5 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{5 e^5 x^2 (a+b x)}{6 b^4 \sqrt{a^2+2 a b x+b^2 x^2}} \]
[Out]
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Rubi [A] time = 0.494543, antiderivative size = 252, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.091 \[ -\frac{(d+e x)^5}{3 b \left (a^2+2 a b x+b^2 x^2\right )^{3/2}}+\frac{10 e^3 (a+b x) (b d-a e)^2 \log (a+b x)}{b^6 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{20 e^2 (b d-a e)^3}{3 b^6 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{5 e (b d-a e)^4}{6 b^6 (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{5 e^4 x (a+b x) (4 b d-3 a e)}{3 b^5 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{5 e^5 x^2 (a+b x)}{6 b^4 \sqrt{a^2+2 a b x+b^2 x^2}} \]
Antiderivative was successfully verified.
[In] Int[((a + b*x)*(d + e*x)^5)/(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]
[Out]
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Rubi in Sympy [A] time = 53.3664, size = 241, normalized size = 0.96 \[ - \frac{\left (d + e x\right )^{5}}{3 b \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}} - \frac{5 e \left (2 a + 2 b x\right ) \left (d + e x\right )^{4}}{12 b^{2} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}} - \frac{10 e^{2} \left (d + e x\right )^{3}}{3 b^{3} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}} + \frac{5 e^{3} \left (2 a + 2 b x\right ) \left (d + e x\right )^{2}}{2 b^{4} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}} - \frac{10 e^{4} \left (a e - b d\right ) \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{b^{6}} + \frac{10 e^{3} \left (a + b x\right ) \left (a e - b d\right )^{2} \log{\left (a + b x \right )}}{b^{6} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((b*x+a)*(e*x+d)**5/(b**2*x**2+2*a*b*x+a**2)**(5/2),x)
[Out]
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Mathematica [A] time = 0.226883, size = 232, normalized size = 0.92 \[ \frac{47 a^5 e^5+a^4 b e^4 (81 e x-130 d)+a^3 b^2 e^3 \left (110 d^2-270 d e x-9 e^2 x^2\right )-a^2 b^3 e^2 \left (20 d^3-270 d^2 e x+90 d e^2 x^2+63 e^3 x^3\right )-5 a b^4 e \left (d^4+12 d^3 e x-36 d^2 e^2 x^2-18 d e^3 x^3+3 e^4 x^4\right )+60 e^3 (a+b x)^3 (b d-a e)^2 \log (a+b x)+b^5 \left (-2 d^5-15 d^4 e x-60 d^3 e^2 x^2+30 d e^4 x^4+3 e^5 x^5\right )}{6 b^6 \left ((a+b x)^2\right )^{3/2}} \]
Antiderivative was successfully verified.
[In] Integrate[((a + b*x)*(d + e*x)^5)/(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]
[Out]
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Maple [B] time = 0.026, size = 495, normalized size = 2. \[{\frac{ \left ( 90\,{x}^{3}a{b}^{4}d{e}^{4}-90\,{x}^{2}{a}^{2}{b}^{3}d{e}^{4}-60\,xa{b}^{4}{d}^{3}{e}^{2}+60\,\ln \left ( bx+a \right ){x}^{3}{a}^{2}{b}^{3}{e}^{5}-20\,{a}^{2}{b}^{3}{d}^{3}{e}^{2}+180\,\ln \left ( bx+a \right ){x}^{2}{a}^{3}{b}^{2}{e}^{5}+180\,\ln \left ( bx+a \right ) x{a}^{4}b{e}^{5}-120\,\ln \left ( bx+a \right ){a}^{4}bd{e}^{4}+180\,{x}^{2}a{b}^{4}{d}^{2}{e}^{3}-270\,x{a}^{3}{b}^{2}d{e}^{4}+270\,x{a}^{2}{b}^{3}{d}^{2}{e}^{3}+60\,\ln \left ( bx+a \right ){x}^{3}{b}^{5}{d}^{2}{e}^{3}+47\,{a}^{5}{e}^{5}-2\,{b}^{5}{d}^{5}+60\,\ln \left ( bx+a \right ){a}^{3}{b}^{2}{d}^{2}{e}^{3}-130\,{a}^{4}bd{e}^{4}+110\,{a}^{3}{b}^{2}{d}^{2}{e}^{3}-5\,a{b}^{4}{d}^{4}e-360\,\ln \left ( bx+a \right ){x}^{2}{a}^{2}{b}^{3}d{e}^{4}-360\,\ln \left ( bx+a \right ) x{a}^{3}{b}^{2}d{e}^{4}+180\,\ln \left ( bx+a \right ){x}^{2}a{b}^{4}{d}^{2}{e}^{3}+180\,\ln \left ( bx+a \right ) x{a}^{2}{b}^{3}{d}^{2}{e}^{3}+60\,\ln \left ( bx+a \right ){a}^{5}{e}^{5}+3\,{x}^{5}{b}^{5}{e}^{5}+30\,{x}^{4}{b}^{5}d{e}^{4}-63\,{x}^{3}{a}^{2}{b}^{3}{e}^{5}-9\,{x}^{2}{a}^{3}{b}^{2}{e}^{5}-60\,{x}^{2}{b}^{5}{d}^{3}{e}^{2}+81\,x{a}^{4}b{e}^{5}-15\,x{b}^{5}{d}^{4}e-15\,{x}^{4}a{b}^{4}{e}^{5}-120\,\ln \left ( bx+a \right ){x}^{3}a{b}^{4}d{e}^{4} \right ) \left ( bx+a \right ) ^{2}}{6\,{b}^{6}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{-{\frac{5}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((b*x+a)*(e*x+d)^5/(b^2*x^2+2*a*b*x+a^2)^(5/2),x)
[Out]
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Maxima [A] time = 0.839522, size = 1493, normalized size = 5.92 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)*(e*x + d)^5/(b^2*x^2 + 2*a*b*x + a^2)^(5/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.287107, size = 575, normalized size = 2.28 \[ \frac{3 \, b^{5} e^{5} x^{5} - 2 \, b^{5} d^{5} - 5 \, a b^{4} d^{4} e - 20 \, a^{2} b^{3} d^{3} e^{2} + 110 \, a^{3} b^{2} d^{2} e^{3} - 130 \, a^{4} b d e^{4} + 47 \, a^{5} e^{5} + 15 \,{\left (2 \, b^{5} d e^{4} - a b^{4} e^{5}\right )} x^{4} + 9 \,{\left (10 \, a b^{4} d e^{4} - 7 \, a^{2} b^{3} e^{5}\right )} x^{3} - 3 \,{\left (20 \, b^{5} d^{3} e^{2} - 60 \, a b^{4} d^{2} e^{3} + 30 \, a^{2} b^{3} d e^{4} + 3 \, a^{3} b^{2} e^{5}\right )} x^{2} - 3 \,{\left (5 \, b^{5} d^{4} e + 20 \, a b^{4} d^{3} e^{2} - 90 \, a^{2} b^{3} d^{2} e^{3} + 90 \, a^{3} b^{2} d e^{4} - 27 \, a^{4} b e^{5}\right )} x + 60 \,{\left (a^{3} b^{2} d^{2} e^{3} - 2 \, a^{4} b d e^{4} + a^{5} e^{5} +{\left (b^{5} d^{2} e^{3} - 2 \, a b^{4} d e^{4} + a^{2} b^{3} e^{5}\right )} x^{3} + 3 \,{\left (a b^{4} d^{2} e^{3} - 2 \, a^{2} b^{3} d e^{4} + a^{3} b^{2} e^{5}\right )} x^{2} + 3 \,{\left (a^{2} b^{3} d^{2} e^{3} - 2 \, a^{3} b^{2} d e^{4} + a^{4} b e^{5}\right )} x\right )} \log \left (b x + a\right )}{6 \,{\left (b^{9} x^{3} + 3 \, a b^{8} x^{2} + 3 \, a^{2} b^{7} x + a^{3} b^{6}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)*(e*x + d)^5/(b^2*x^2 + 2*a*b*x + a^2)^(5/2),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{\left (a + b x\right ) \left (d + e x\right )^{5}}{\left (\left (a + b x\right )^{2}\right )^{\frac{5}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x+a)*(e*x+d)**5/(b**2*x**2+2*a*b*x+a**2)**(5/2),x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (b x + a\right )}{\left (e x + d\right )}^{5}}{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac{5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)*(e*x + d)^5/(b^2*x^2 + 2*a*b*x + a^2)^(5/2),x, algorithm="giac")
[Out]